$\frac{x^2-4x+4}{x^2-x-12}$
$\int\left(\frac{x^3}{1-3x^4}\right)dx$
$\lim_{x\to\infty}\left(4x-ln\left(x\right)\right)$
$xy\:=\:1\:+\:x^2$
$\frac{1}{6}x^{2}+\frac{1}{3}\cdot\frac{1}{3}$
$-9\:-\:\left(-5\right)$
$\sqrt{\frac{6x^3}{tan\frac{x}{2}}}$
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