$\lim_{x\to0}\left(\frac{x^2}{1-3\cos\left(x\right)}\right)$
$\left(2xy+z\right)^2$
$\left(3ba^3\right)^4$
$\frac{-8x^2+12xy-4y^2}{x+y}$
$\left(-7\right).\left(+2\right).\left(-3\right).\left(-1\right)$
$\left(28m^2-13m-6\right)\left(4m-3\right)$
$x y ^ { 2 } = 9$
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