$31-2^2-1^3\cdot3$
$\int_0^{\frac{\pi}{6}}\left(\frac{\sec^2\left(x\right)}{1+9\tan^2\left(x\right)}\right)dx$
$\frac{dy}{dx}=5y^5$
$\sqrt{125x^5}$
$3x^2-7x+12=0$
$-19<5u+1$
$4x^2-16x-36$
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