$3^2+2^3$
$94\:=25h\:+\:69$
$\:-\frac{h}{3}-4=13$
$2x-14=4x+6$
$=\:x^{3\sqrt{4x}}$
$\int\frac{\left(2x+1\right)}{\left(x^2-6x+13\right)^2}dx$
$\frac{1}{\:\left(a-b\right)\left(a-c\right)}+\frac{1}{\left(b-c\right)\left(b-a\right)}$
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