$4\left(-15-3p\right)-4\left(-p+4\right)$
$\int_{-3}^1\frac{6}{x^2}dx$
$x^2-8x+61=16$
$3y-y+8y$
$\left(3x^2y^3+4xy\right)dx+\left(3x^3y^2+2x^2\right)dy=0$
$\frac{3an-4a-6bn+8b}{6n^2-5n-4}$
$\lim\:_{x\to\:\infty}\left(\frac{9x^4+4x^2}{3x^4-15}\right)$
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