$\left(\frac{z-x}{2m+n}\right);\:m=-2;\:n=3;\:z=\frac{1}{2};\:x=\frac{1}{3}$
$\int\frac{1}{x^2-2x+15}dx$
$\left(2a+3b\right)^2-\left(2a-3b\right)^2$
$4b\cdot\frac{\left(b-4\right)}{2}$
$-4x\left(7-3x\right)=0$
$-2x^5\:-4x^3$
$6x-6y+14$
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