$\int\frac{\left(x-3\right)}{\left(\sqrt{4-x^2}\right)}dx$
$\frac{x^2-4}{x^3-10}$
$y''+2y'+4y=0$
$\frac{2}{\left(s+1\right)^2\left(s+4\right)}$
$\frac{x^2-9}{a^2+7a-8}\cdot\frac{a^2-64}{x+3}$
$\frac{\left(b-a\right)^2}{a^2-b^2-ab}$
$\frac{x+x}{x}$
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