$y=3x^{-\frac{1}{4}}$
$-7x^2+x=0$
$5x-4=51$
$4x^3+3x^2+5x+6;\:x=2$
$f\left(x\right)=\left(5x^2+1\right)\left(2\sqrt{x}-1\right)$
$\lim_{x\to\infty}\left(\frac{x}{ln\left(1+2e^x\right)}\right)$
$y^2-3y+9$
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