$\sqrt{x}x\sqrt[3]{2x^2}$
$\left(y+2\right)x^2$
$5x\:+\:1\:<\:6$
$\frac{x^4+16}{x-2}$
$x^2\left(b+g\right)+y^2\left(b+g\right)$
$\left(6x^2-3\right)^2$
$\left(-7+2\right)\left(-6+3-2\right)$
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