$\int\frac{x+3}{x^2-4x+3}dx$
$\frac{x^{2}+3x+5}{x+1}$
$\frac{\sec a}{\tan a+\cot a}=\sin$
$e=\left(x-2\right)^2+2\left(2x-3\right)-\left(x^2+1\right)+3$
$\int3^{5x-2}dx$
$\left(-3^2y^4\right)^5$
$9-3x>4\left(2x-1\right)$
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