$4n^{2-1=0}$
$\frac{d}{dx}-\frac{x}{5y}$
$\left(10+4x\right)\left(10-4x\right)$
$\left(x^3y^3-6\right)\left(x^3y^3+98\right)$
$\frac{dy}{dx}=\frac{\left(x^2+y^2\right)}{-2xy}$
$\frac{10\ln6}{0.20}$
$2\frac{dy}{dx}+3y=0$
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