$x-1.25=0.15x-6.35$
$\lim\:_{x\to\:\infty\:}\left(\frac{6z^2+2z-7}{4z^3+2z-7}\right)$
$5mn-mn^2-4mn^3$
$\frac{x^2}{16}+\frac{xy}{2}+y^2$
$m^2-4m-5$
$4f>32$
$\frac{dy}{dx}=-\frac{\left(\cos\left(x\right)\right)^2}{\sin\left(y\right)}$
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