$\int\sin^4\left(\frac{1}{2}\right)dt$
$\left(x^2y^3-1\right)^3$
$-7\cdot3+6$
$y'+ycosx=4cosx,y\left(0\right)=6$
$x+12\le-10$
$3x^2+7x+5\left(x+3\right)+x^2$
$\left(-13\right)x\left(+4\right)$
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