$m^6\:-\:4$
$\left(x+y\left(x\right)+1\right)\cdot y'\left(x\right)=1$
$\lim_{x\to0}\left(\frac{x-arcsinx}{sin^3x}\right)$
$5x^2\:+\:15x\:+\:10\:=\:0\:\:$
$-12+-7+-18+-7$
$\frac{2}{x+1}-\frac{2x}{x+4}$
$7\:\cdot\left(9+5\right)$
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