$\left(2b+4\right)^2$
$\frac{\left(2x^2+3x-3\right)}{\left(x-4\right)}$
$\lim_{x,y\to0,0}\left(3\sqrt{x^3}+\sqrt{5y}\right)$
$\frac{x+1}{x-6}>7$
$45\cdot13$
$\frac{1}{2}\int1\:+\:tan^2\left(u\right)\:sec\:^2\left(u\right)du$
$1^{64}$
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