$4n\cdot4m^2n^3$
$\frac{dy}{dt}\:2y+1$
$\frac{dy}{dx}=\frac{y\cos x}{1+2y^{2}}$
$2x=-2$
$\frac{dy}{dx}=\frac{\arcsin\left(x\right)}{y^2\sqrt{1-x^2}}$
$\left(6a+13\right)^2$
$f\left(x\right)\:=\:2\left(3x\:-\:6\right)\:^2\:-\:18$
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