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Expand the fraction $\frac{x+1}{x^2+16}$ into $2$ simpler fractions with common denominator $x^2+16$
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$\int\left(\frac{x}{x^2+16}+\frac{1}{x^2+16}\right)dx$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int((x+1)/(x^2+16))dx. Expand the fraction \frac{x+1}{x^2+16} into 2 simpler fractions with common denominator x^2+16. Expand the integral \int\left(\frac{x}{x^2+16}+\frac{1}{x^2+16}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{x}{x^2+16}dx results in: -\ln\left(\frac{4}{\sqrt{x^2+16}}\right). The integral \int\frac{1}{x^2+16}dx results in: \frac{1}{4}\arctan\left(\frac{x}{4}\right).