$\lim_{x\to0}\left(\frac{\left(x-2\right)^2-4}{-2x}\right)$
$123^2-4^3$
$8u-10u+8u$
$\frac{5^4}{5^1}$
$\frac{\left(2x^2\right)^2}{20x^3}$
$m\left(n-2\right)+2-n$
$\int2xe^{\left(2x+\pi\right)}dx$
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