$r^2-14r+8=0$

$6\log_{64}\left(v\right)=2$

$\frac{1-\left(\sin\left(x\right)\right)^4}{1+\:\left(\sin\left(x\right)\right)^2}=\left(\cos\left(x\right)\right)^2$

$\left(x+4y+z\right)\left(x-4y-z\right)$

$\lim_{x\to\infty}\:\frac{3x^2+5}{x^2-2}$

$1\left(6\cdot6+1\right)$

$2\cdot0.1505\:+\:0.301$