$\lim_{x\to0}\left(\frac{\sin\left(10x\right)}{2x}\right)$

$\left(x-3\right)-2\left(2x-2\right)$

$3\left(4u\right)$

$\frac{d^5}{dx^5}\left(\tanh\left(x\right)\right)$

$\frac{dy}{dx}+y\tan\left(x\right)-\sin\left(2x\right)=0$

$9.32-0.467$

$\left(\frac{1}{2r^6}\right)-6$