$16q^2+48+36$
$\frac{ds}{dt}=-3.5\left(s\right)\left(i\right)$
$\int\sqrt{\tan\left(3\right)+4}dx$
$\frac{x^5-1}{x^4-1}$
$2y^2-3y+3,x=-2,\:y=-1$
$\int_0^1\left(3x^2+8x\right)dx$
$\frac{7x+1}{5}=-x^2$
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