$6x\le-18$
$\frac{x}{\left(x-1\right)\left(x+1\right)+\left(x+2\right)}$
$f\left(x\right)=4.1^2\left(3\sqrt{1}-8\sqrt[3]{1}-2\right)$
$\left(\left(\frac{6zw^4}{8z^2w^6}\right)^3\right)$
$8x+32$
$\left(4x^2+2\right)\left(3x^3-1\right)$
$2;\:x=7;\:y=10$
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