$\left(1-3x\right)\left(1+12x+60x^2+160x^3+240x^4\right)$
$x^2+1\:=\:10$
$\int\left(\frac{e^t}{t}\right)dt$
$3x^2\left(7x+8y+9z^2\right)$
$\frac{42x^5-8x^3+15}{6x^3+3}$
$\frac{b^5-243}{b-3}$
$x^2+6x+7x^2-8x$
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