$\frac{16}{x^2+4x}=\frac{8}{x}$
$3x-7>0$
$\frac{1}{cos}-1$
$1+\tan^2\infty=\frac{1}{\cos^2\infty}$
$\frac{62}{491.226}$
$25a^2-125$
$\lim_{x\to\infty}\frac{10x+1}{\ln x}$
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