$x^2\le4x-3$
$4p^2m^2-12p^3m^3+16p^4m^4-20p^5m^5$
$\int\frac{\ln\left(x\right)}{9}dx$
$4=\left(x+y\right)^{2}$
$9+6b^6+b^{12}$
$49a^{10}n-\frac{b^{12x}}{81}$
$6\left(1x^2+\left(-1y\right)^2\right)dx+6\cdot1x\cdot\left(-1y\right)\:dy=0$
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