$\tan^2\left(a\right)=\frac{1}{\cos^2\left(a\right)}-1$
$2m-n=5$
$\int e^{\frac{x^4}{4}}x^3dx$
$\left(2x^3+3x^2+4\right)\cdot\left(x+2\right)$
$x-\frac{1}{x}-3$
$\frac{4-6x}{5}\le\frac{1}{2}-3\left(2-3x\right)$
$tg^2x+3tgx+2=0$
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