$\left(3c-4d\right)^3$
$\frac{12}{x-5}=\frac{3}{x-5}-3$
$\frac{d}{dx}\left(e^{xy}-y=\arcsin\left(2y\right)\right)$
$49x^2+14x+1=0$
$x^2-20x+84$
$3x^5-2x^4+2x^2+4-1$
$\frac{5x^2+2x-1}{x+3}$
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