$-8+2\:x\:5\:-1$
$\frac{3x-1}{x^2-1}\le1$
$x^4-x^2x\:+x^3+4x^2\:5+7x^2-4x+6$
$\left(x^{-4}\right)^{-4}$
$3^2-2+5-9+12-15+3$
$7x\left(x^2\right)$
$\frac{\left(9x^2y^3-18x^2y^5+6xy^7\right)}{-3xy}$
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