$5tanb=10$
$\int\sqrt{16+6x-x^2}dx$
$\frac{x^3-x^2+2x+10}{x^2-8}$
$\frac{6x}{x^{2+4}}$
$-\:0.3\:-\:9$
$\int8xe^{-3x}dx$
$\lim_{x\to0}\:\left(cosx\right)^{\left(x+1\right)}$
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