$a^2+4a-12=0$
$\int\frac{x}{\left(x-2\right)\left(x+2\right)}dx$
$\frac{x-3}{x-6}-1=\frac{3}{x-6}$
$f\left(x\right)=3x^2-4x+10x$
$5x^2=125$
$\int\left(\frac{5x+4}{\left(10x^2+16x\right)^4}\right)dx$
$34\:-\:\left(-23\right)$
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