$p^2-5p=-4$
$\frac{1}{6}-12x-16$
$3\cdot\left(g-4v\right)$
$x^3-26x^2+120x-128$
$\frac{dy}{dx}-7y=7$
$\frac{3}{2}m-4n$
$\int\left(\frac{x\left(5x-12\right)\left(x-4\right)}{x\left(x-4\right)}\right)dx$
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