$\left(9x^4-7y^6\right)^2$
$12x^2-42x+5$
$\frac{880}{4}$
$\left(x+4\right)\left(x+3\right)+\left(x+6\right)\left(x+1\right)-2\left(x^2+7x+5\right)$
$x^2+2x+mx;\:x=1;\:m=-1$
$\left(\frac{x^3+3x^2+2}{x-1}\right)^3$
$-4x^2+3x+27$
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