$\int\frac{64\cos\left(x\right)^3}{4\cos\left(x\right)}dx$
$\int x ^ { - 73 } d x$
$\left(\frac{1}{2}x^2+\frac{3}{5}x^3\right)^2$
$\left(x-3\right)^2=12$
$4x-9\le19$
$3x^2-6x=24$
$\frac{6}{1-\sin\left(x\right)}+\frac{6}{1+\sin\left(x\right)}=12\sec^2\left(x\right)$
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