$12\:-\:3\:+\:5\:-\:8\:+\:1\:-10$
$\left(x^2-\frac{4}{5}\right)\left(2x^2-\frac{5}{4}\right)$
$-19\cdot37$
$\left(16p+20q\right).\left(16p-20q\right)$
$10.54403\left(0.108\right)^2-2.49416\left(0.108\right)+0.14827$
$4\left(4+b''\right)$
$7\:-\:\left(\:-\:9\:+\:8\:\right)\:-\:10$
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