$\left(4x^6\right)^2\left(xy^4\right)^2$
$\left(\frac{2}{3}+4xy\right)\left(\frac{1}{5}+4xy\right)$
$4x^2+x^3-6x^2$
$p\left(x^3-5x^2+4x-6\right)\left(x-4\right)$
$\left(2a\right)^3\cdot\left(3c\right)^2$
$0-2\cdot0\le4$
$\frac{dy}{dx}=\frac{y^3}{\left(x+4\right)}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!