$\lim_{h\to0}\frac{\sqrt{h^2+4h+5}-\sqrt{5}}{h}$
$2x-9\:>5$
$\frac{x}{2}+3y+5=0$
$\frac{1.253}{12}$
$2\cos^3\left(x\right)-\cos\left(x\right)=0$
$\frac{2x^7y^5}{3x^3y\cdot4x^2y^3}$
$\left(4x-3\right)\left(2x-7\right)$
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