$x+x+2=\frac{\left(x+2\right)\left(x+4\right)}{4}$
$\sqrt[4]{81^6}$
$\frac{d}{dx}\left(3\arcsin\left(x\right)\right)$
$\int\frac{x^2+2}{x^2\left(x^2+4\right)}dx$
$-18+6x+2-x$
$9x^2+6x-4$
$-2x^2+16x+11$
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