$\left(4-1\right)^2\cdot5$
$-4+-\infty$
$xy-4y=0$
$2+2+4t^2$
$\int z^{-4}ln\left(\frac{1}{z^3}\right)dz$
$\frac{2xy^{3}}{4x^{4}y^{3}}$
$\frac{d}{dx}5tan^5$
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