$6^{-4}\cdot6^4$
$\lim_{x\to+\infty}\left(1+\frac{1}{3x}\right)^{6x}$
$\int\frac{\left(7x\right)}{\sqrt{4-x^2}}dx$
$2\:cos\:x\::\:sen\:x=1$
$5+3-12+4-1+16-11-2-7$
$\left(21-a\right)^2$
$\sin\left(0\right)\cos\left(0\right)\sec\left(0\right)\csc\left(0\right)=1$
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