$\frac{m^{27}-1}{m^3-1}$

$f\left(x\right)=\left(x+2\right)\left(x-3\right)\left(x-4\right)\left(3x^2\:-4x+2\right)$

$\lim_{x\to\infty}\left(\frac{1}{0.75^x}\right)$

$\frac{d^2}{dx^2}\left(\frac{x^2}{x^2+4}\right)$

$\left(5x+5\right)^{3x+3}$

$\left(3x^4+6\right)\left(3x^4-3\right)$

$4x-2\left(x-3\right)$