$9\:\left(\frac{2}{3}\right)$

$\int tan^{-1}\cdot6xdx$

$\left(2\sin\left(x\right)-\sqrt{3}\right)\left(2\cos\left(x\right)+\sqrt{2}\right)=0$

$c1x$

$\sec^2b+\tan^2b=2\tan^2b+1$

$\frac{d^{2}y}{dx^{2}}\text{given}y^{2}=6-\frac{5}{x}$

$\left(2x^3+y\right)\left(-7x^3+y\right)$