$\sqrt{6-4}$
$1^2\cdot1^2$
$\frac{1-\cos\left(x\right)^2}{\sin\left(x\right)^2}=\tan\left(x\right)$
$x^2+27=0$
$\left(x+2y-7\right)^2$
$y^'=3x^3y^{12}$
$ax-5ax+4ax$
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