$\int\frac{1}{\left(t^2+9\right)^2}dt$
$49^2m-m$
$2.5x-1.9y+3.1x-0.6y$
$\sqrt{240y^4}$
$\int\left(\frac{3x^2-4}{x^2}\right)dx$
$y''-3y'-10y=0;\:y\left(0\right)=1\:;y'\left(0\right)=10$
$\left(bn+3x\right)\left(bn+2x\right)$
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