$2=b-8$
$2tan^{\left(3\right)}x-\:3tan^{\left(2\right)}x\:-\:2tan\:x=\:0$
$\left(4x^3+8z\right)\cdot\left(4x-8z^3\right)$
$\frac{d}{dx}\:x+c$
$\frac{x^2+4x-6}{x+1}$
$10m+5m-3m$
$16x^8-16$
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