$\frac{dy}{dx}=\frac{x+1}{y},\:y\left(0\right)=-2$
$x^2-10x+100$
$-3^2-16$
$\frac{3}{x^3-8}=\frac{1}{x-2}$
$\int\frac{3x+10}{x\left(x+2\right)^2}dx$
$\lim_{x\to\infty}\left(\frac{\left(x\right)}{x+3}\right)^x$
$0^3-6\left(0\right)^2+11\left(0\right)-6$
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