$\left(2x^2y\:+\:3m^3\right)^2$
$12-9+3-6+7+4$
$\log\left(u\right)-\log\left(9\right)=2$
$3\cdot0^4-5\cdot0^2-1$
$9\:\left(-6\right)$
$\frac{-12x^{10}y^3}{6x^8y}$
$x^2y'=xy$
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