$\left(x+2\right)\left(x-1\right)+26\le\left(x+4\right)\left(x+5\right)$
$\frac{2x^4}{-3xy^2}$
$\left(2x^4-6x\right)^3$
$x^3+5x-1:x^2+1x\:$
$2\left(a+2b\right)-a-2b$
$enteros$
$\int\left(x^3-2\right)^2\cdot3x^2dx$
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