$8xy-3x-3yx+2y$
$\left(1+\cot^2x\right)\tan^2x=\cot^2x$
$x3+2x+4;\:x=3$
$\frac{d}{dx}\left(6x-2\right)^4\left(5x^2+9\right)^4$
$\frac{x}{x-3}-\frac{14x-9}{x^2+5x-24}$
$8y^2-11y+3=0$
$\left(a^2b-c\right)\left(a^2b+2c\right)$
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