$\frac{5}{x^2+3x-4}$
$a^3-b^{3\:}=\:0\:$
$16b^2+16b+4$
$5x-2\cdot5x+2$
$4m^3n-2mn+6m$
$\int_{60}^{\infty}\left(0.01e^{-0.01}\right)dx$
$\int_{-2}^1\left(-x^2+4x+5\right)dx$
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