$x^2-10x\:-11$
$\int\frac{1}{\left(x+3\right)\left(x-4\right)}dx$
$\lim_{x\to0}\left(\frac{\left(x^2+3x+2\right)^2}{\left(x^2-1\right)\left(x^3+1\right)}\right)$
$-\int e^3xdx$
$-4x^2+4x+8$
$\lim_{x\to-3}\left(\frac{x^2-9}{4x^2+22x+30}\right)$
$10x^2-20x-93=0$
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