$\int_{-6}^{-10}\frac{1}{x+2}dx$
$\left(2xy+2\right)^2$
$x\left(x+8y\right)y'=y\left(x-8y\right)$
$\frac{dy}{dx}=\frac{yx-y+x-1}{x+2}$
$6^{\frac{1}{3}}=\sqrt[3]{6}$
$\left(5-7\right)-\left(11-4+2\right)$
$\left(a^6+7\right)x^{3a+8}\:y^{30}$
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